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单词 Taylor’s Theorem
释义
Taylor’s Theorem

Mathematics
  • Applied to a suitable function f, Taylor’s Theorem gives a polynomial that is an approximation to f(x).

    Theorem

    Let f be a real function on an open interval I, such that the derived functions f(r )(r = 1,…, n) are continuous functions and suppose that a ε‎ I. Then, for all x in I,

    f(x)=f(a)+f′(a)1!(x−a)+f″(a)2!(x−a)2+…+f(n−1)(a)(n−1)!(x−a)n−1+Rn,

    where Rn denotes the remainder term Rn.

    Two possible forms for Rn are

    Rn=1(n−1)!∫axf(n)(t)(x−t)n−1dtandRn=f(n)(c)n!(x−a)n,

    where c lies between a and x. By taking x = a + h, where a + h ε‎ I, the formula

    f(a+h)=f(a)+f′(a)1!h+f″(a)2!h2+⋯+f(n−1)(a)(n−1)!hn−1+Rn

    is obtained. This enables f(a + h) to be determined up to a certain degree of accuracy, the remainder Rn giving the error. Suppose now that f is infinitely differentiable in I and that Rn → 0 as n → ∞; then an infinite series can be obtained whose sum is f(x). In such a case, it is customary to write

    f(x)=f(a)+f′(a)1!(x−a)+f″(a)2!(x−a)2+⋯.

    This is the Taylor series (or expansion) for f at (or about) a. The special case with a = 0 is the Maclaurin series for f. Note that the Taylor series of an infinitely differentiable function f(x) can converge without converging to f(x); it is important that the remainder term tends to 0. For example, the function

    f(x)={exp(−1/x2),x≠0,0,x=0,

    is infinitely differentiable at 0 with f(n)(0) = 0 for all n. Thus, the Taylor series converges, but to the zero function, rather than to f(x).

    The Taylor series for a real function f(x,y) of two variables, which has partial derivatives of all orders, states that

    f(a+h,b+k)=f(a,b)+(fx(a,b)h+fy(a,b)k)+12!(fxx(a,b)h2+2fxy(a,b)hk+fyy(a,b)k2)+⋯.

    In complex analysis, a function f(z) which is holomorphic at a point a has a Taylor series

    f(z)=∑k=0∞f(k)(a)k!(z−a)k

    which is convergent in a neighbourhood of a. See also Cauchy’s formula for derivatives.


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